[S. James]

I'm writing a class(.h) file involving complex numbers and need to overload the << and >> so I can use cin and cout .

The class allows users to use complex numbers in the form a+bi.
So, the private parts of the class are real(a part), imag(b part) and expoi (the exponent of i. so 3 = expoi in i^3)

I succefully overloaded all the other things, so here's what the class can do.
class Complex // keeps track of a Number in the form a +bi
{
private:
double real; // this is the "a" part
double imag; // this is the "b" part
int expoi; // this is the exponent of i
public:
double Real();// Returns Real part of number
double Imaginary(); // Returns imaginary part of number
void Show(); // prints out complex number on screen
Complex operator +(Complex Num);
Complex operator -(Complex Num);
Complex operator *(Complex Num);
Complex operator=(Complex Num);
Complex operator==(Complex Num);
Complex operator<<(Complex Num);
Complex operator>>(Complex Num);
};
I did the << operator as void funtion but my prof wants me to overload the operator.

void Complex :: Show()
{
cout << real;

if(expoi %4 == 0) // if expoi is divisible by 4 then i = 1
{
if (imag < 0)
cout << " - "<< imag*-1 << endl;
else
cout << " + " << imag << endl;
}

else if(expoi %3 == 0) // if expoi is divisible by 3 then i = -i
{
if (imag < 0)
cout << " + "<< imag*-1 << 'i' << endl;
else
cout << " - " << imag << 'i' << endl;
}

else if (expoi %2 == 0) // if expoi is not divisible by 4 but divisible by 2 then i = -1
{
if (imag < 0)
cout << " + "<< imag*-1 << endl;
else
cout << " - " << imag << endl;
}

else // if expoi is not divisible by 2,3,or 4 then i = i
{
if (imag < 0)
cout << " - "<< imag*-1 << 'i' << endl;
else
cout << " + " << imag << 'i' << endl;
}
}